因为x→0，所以原式用等价无穷小替换后得： limsinxsin（sinx）/x³ 由sin（sinx）=sinxsin³x/3！0（x³）得： 原式=limsinxsin lim x → 0f ( x2) − f ( 0) 3x2 = lim x → 0sin(√x2) − sin(0) 3x2 = lim x → 0sin(x) 3x2 = " 0 0 " Than L'hopital again lim x → 0cos(x) 6x This limit does not exist calculus integration limits definiteintegrals Share¿Cómo calcular este límite limx→a (sinxsina) /xa?
Please Show Working Compute The Following Chegg Com
